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s^2-169=0
a = 1; b = 0; c = -169;
Δ = b2-4ac
Δ = 02-4·1·(-169)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-26}{2*1}=\frac{-26}{2} =-13 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+26}{2*1}=\frac{26}{2} =13 $
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